3.692 \(\int \frac{x (a+b x)^{5/2}}{(c+d x)^{5/2}} \, dx\)

Optimal. Leaf size=222 \[ -\frac{2 (a+b x)^{5/2} (7 b c-3 a d)}{3 d^2 \sqrt{c+d x} (b c-a d)}+\frac{5 b (a+b x)^{3/2} \sqrt{c+d x} (7 b c-3 a d)}{6 d^3 (b c-a d)}-\frac{5 b \sqrt{a+b x} \sqrt{c+d x} (7 b c-3 a d)}{4 d^4}+\frac{5 \sqrt{b} (7 b c-3 a d) (b c-a d) \tanh ^{-1}\left (\frac{\sqrt{d} \sqrt{a+b x}}{\sqrt{b} \sqrt{c+d x}}\right )}{4 d^{9/2}}-\frac{2 c (a+b x)^{7/2}}{3 d (c+d x)^{3/2} (b c-a d)} \]

[Out]

(-2*c*(a + b*x)^(7/2))/(3*d*(b*c - a*d)*(c + d*x)^(3/2)) - (2*(7*b*c - 3*a*d)*(a + b*x)^(5/2))/(3*d^2*(b*c - a
*d)*Sqrt[c + d*x]) - (5*b*(7*b*c - 3*a*d)*Sqrt[a + b*x]*Sqrt[c + d*x])/(4*d^4) + (5*b*(7*b*c - 3*a*d)*(a + b*x
)^(3/2)*Sqrt[c + d*x])/(6*d^3*(b*c - a*d)) + (5*Sqrt[b]*(7*b*c - 3*a*d)*(b*c - a*d)*ArcTanh[(Sqrt[d]*Sqrt[a +
b*x])/(Sqrt[b]*Sqrt[c + d*x])])/(4*d^(9/2))

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Rubi [A]  time = 0.118998, antiderivative size = 222, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 6, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.3, Rules used = {78, 47, 50, 63, 217, 206} \[ -\frac{2 (a+b x)^{5/2} (7 b c-3 a d)}{3 d^2 \sqrt{c+d x} (b c-a d)}+\frac{5 b (a+b x)^{3/2} \sqrt{c+d x} (7 b c-3 a d)}{6 d^3 (b c-a d)}-\frac{5 b \sqrt{a+b x} \sqrt{c+d x} (7 b c-3 a d)}{4 d^4}+\frac{5 \sqrt{b} (7 b c-3 a d) (b c-a d) \tanh ^{-1}\left (\frac{\sqrt{d} \sqrt{a+b x}}{\sqrt{b} \sqrt{c+d x}}\right )}{4 d^{9/2}}-\frac{2 c (a+b x)^{7/2}}{3 d (c+d x)^{3/2} (b c-a d)} \]

Antiderivative was successfully verified.

[In]

Int[(x*(a + b*x)^(5/2))/(c + d*x)^(5/2),x]

[Out]

(-2*c*(a + b*x)^(7/2))/(3*d*(b*c - a*d)*(c + d*x)^(3/2)) - (2*(7*b*c - 3*a*d)*(a + b*x)^(5/2))/(3*d^2*(b*c - a
*d)*Sqrt[c + d*x]) - (5*b*(7*b*c - 3*a*d)*Sqrt[a + b*x]*Sqrt[c + d*x])/(4*d^4) + (5*b*(7*b*c - 3*a*d)*(a + b*x
)^(3/2)*Sqrt[c + d*x])/(6*d^3*(b*c - a*d)) + (5*Sqrt[b]*(7*b*c - 3*a*d)*(b*c - a*d)*ArcTanh[(Sqrt[d]*Sqrt[a +
b*x])/(Sqrt[b]*Sqrt[c + d*x])])/(4*d^(9/2))

Rule 78

Int[((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> -Simp[((b*e - a*f
)*(c + d*x)^(n + 1)*(e + f*x)^(p + 1))/(f*(p + 1)*(c*f - d*e)), x] - Dist[(a*d*f*(n + p + 2) - b*(d*e*(n + 1)
+ c*f*(p + 1)))/(f*(p + 1)*(c*f - d*e)), Int[(c + d*x)^n*(e + f*x)^(p + 1), x], x] /; FreeQ[{a, b, c, d, e, f,
n}, x] && LtQ[p, -1] && ( !LtQ[n, -1] || IntegerQ[p] ||  !(IntegerQ[n] ||  !(EqQ[e, 0] ||  !(EqQ[c, 0] || LtQ
[p, n]))))

Rule 47

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^n)/(b*
(m + 1)), x] - Dist[(d*n)/(b*(m + 1)), Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 1), x], x] /; FreeQ[{a, b, c, d},
x] && NeQ[b*c - a*d, 0] && GtQ[n, 0] && LtQ[m, -1] &&  !(IntegerQ[n] &&  !IntegerQ[m]) &&  !(ILeQ[m + n + 2, 0
] && (FractionQ[m] || GeQ[2*n + m + 1, 0])) && IntLinearQ[a, b, c, d, m, n, x]

Rule 50

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^n)/(b*
(m + n + 1)), x] + Dist[(n*(b*c - a*d))/(b*(m + n + 1)), Int[(a + b*x)^m*(c + d*x)^(n - 1), x], x] /; FreeQ[{a
, b, c, d}, x] && NeQ[b*c - a*d, 0] && GtQ[n, 0] && NeQ[m + n + 1, 0] &&  !(IGtQ[m, 0] && ( !IntegerQ[n] || (G
tQ[m, 0] && LtQ[m - n, 0]))) &&  !ILtQ[m + n + 2, 0] && IntLinearQ[a, b, c, d, m, n, x]

Rule 63

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[{p = Denominator[m]}, Dist[p/b, Sub
st[Int[x^(p*(m + 1) - 1)*(c - (a*d)/b + (d*x^p)/b)^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] &
& NeQ[b*c - a*d, 0] && LtQ[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntLinearQ[a,
b, c, d, m, n, x]

Rule 217

Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Subst[Int[1/(1 - b*x^2), x], x, x/Sqrt[a + b*x^2]] /; FreeQ[{a,
b}, x] &&  !GtQ[a, 0]

Rule 206

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTanh[(Rt[-b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[-b, 2]), x]
/; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rubi steps

\begin{align*} \int \frac{x (a+b x)^{5/2}}{(c+d x)^{5/2}} \, dx &=-\frac{2 c (a+b x)^{7/2}}{3 d (b c-a d) (c+d x)^{3/2}}+\frac{(7 b c-3 a d) \int \frac{(a+b x)^{5/2}}{(c+d x)^{3/2}} \, dx}{3 d (b c-a d)}\\ &=-\frac{2 c (a+b x)^{7/2}}{3 d (b c-a d) (c+d x)^{3/2}}-\frac{2 (7 b c-3 a d) (a+b x)^{5/2}}{3 d^2 (b c-a d) \sqrt{c+d x}}+\frac{(5 b (7 b c-3 a d)) \int \frac{(a+b x)^{3/2}}{\sqrt{c+d x}} \, dx}{3 d^2 (b c-a d)}\\ &=-\frac{2 c (a+b x)^{7/2}}{3 d (b c-a d) (c+d x)^{3/2}}-\frac{2 (7 b c-3 a d) (a+b x)^{5/2}}{3 d^2 (b c-a d) \sqrt{c+d x}}+\frac{5 b (7 b c-3 a d) (a+b x)^{3/2} \sqrt{c+d x}}{6 d^3 (b c-a d)}-\frac{(5 b (7 b c-3 a d)) \int \frac{\sqrt{a+b x}}{\sqrt{c+d x}} \, dx}{4 d^3}\\ &=-\frac{2 c (a+b x)^{7/2}}{3 d (b c-a d) (c+d x)^{3/2}}-\frac{2 (7 b c-3 a d) (a+b x)^{5/2}}{3 d^2 (b c-a d) \sqrt{c+d x}}-\frac{5 b (7 b c-3 a d) \sqrt{a+b x} \sqrt{c+d x}}{4 d^4}+\frac{5 b (7 b c-3 a d) (a+b x)^{3/2} \sqrt{c+d x}}{6 d^3 (b c-a d)}+\frac{(5 b (7 b c-3 a d) (b c-a d)) \int \frac{1}{\sqrt{a+b x} \sqrt{c+d x}} \, dx}{8 d^4}\\ &=-\frac{2 c (a+b x)^{7/2}}{3 d (b c-a d) (c+d x)^{3/2}}-\frac{2 (7 b c-3 a d) (a+b x)^{5/2}}{3 d^2 (b c-a d) \sqrt{c+d x}}-\frac{5 b (7 b c-3 a d) \sqrt{a+b x} \sqrt{c+d x}}{4 d^4}+\frac{5 b (7 b c-3 a d) (a+b x)^{3/2} \sqrt{c+d x}}{6 d^3 (b c-a d)}+\frac{(5 (7 b c-3 a d) (b c-a d)) \operatorname{Subst}\left (\int \frac{1}{\sqrt{c-\frac{a d}{b}+\frac{d x^2}{b}}} \, dx,x,\sqrt{a+b x}\right )}{4 d^4}\\ &=-\frac{2 c (a+b x)^{7/2}}{3 d (b c-a d) (c+d x)^{3/2}}-\frac{2 (7 b c-3 a d) (a+b x)^{5/2}}{3 d^2 (b c-a d) \sqrt{c+d x}}-\frac{5 b (7 b c-3 a d) \sqrt{a+b x} \sqrt{c+d x}}{4 d^4}+\frac{5 b (7 b c-3 a d) (a+b x)^{3/2} \sqrt{c+d x}}{6 d^3 (b c-a d)}+\frac{(5 (7 b c-3 a d) (b c-a d)) \operatorname{Subst}\left (\int \frac{1}{1-\frac{d x^2}{b}} \, dx,x,\frac{\sqrt{a+b x}}{\sqrt{c+d x}}\right )}{4 d^4}\\ &=-\frac{2 c (a+b x)^{7/2}}{3 d (b c-a d) (c+d x)^{3/2}}-\frac{2 (7 b c-3 a d) (a+b x)^{5/2}}{3 d^2 (b c-a d) \sqrt{c+d x}}-\frac{5 b (7 b c-3 a d) \sqrt{a+b x} \sqrt{c+d x}}{4 d^4}+\frac{5 b (7 b c-3 a d) (a+b x)^{3/2} \sqrt{c+d x}}{6 d^3 (b c-a d)}+\frac{5 \sqrt{b} (7 b c-3 a d) (b c-a d) \tanh ^{-1}\left (\frac{\sqrt{d} \sqrt{a+b x}}{\sqrt{b} \sqrt{c+d x}}\right )}{4 d^{9/2}}\\ \end{align*}

Mathematica [C]  time = 0.140953, size = 110, normalized size = 0.5 \[ \frac{2 (a+b x)^{7/2} \left ((c+d x) (7 b c-3 a d) \sqrt{\frac{b (c+d x)}{b c-a d}} \, _2F_1\left (\frac{3}{2},\frac{7}{2};\frac{9}{2};\frac{d (a+b x)}{a d-b c}\right )+7 c (a d-b c)\right )}{21 d (c+d x)^{3/2} (b c-a d)^2} \]

Antiderivative was successfully verified.

[In]

Integrate[(x*(a + b*x)^(5/2))/(c + d*x)^(5/2),x]

[Out]

(2*(a + b*x)^(7/2)*(7*c*(-(b*c) + a*d) + (7*b*c - 3*a*d)*(c + d*x)*Sqrt[(b*(c + d*x))/(b*c - a*d)]*Hypergeomet
ric2F1[3/2, 7/2, 9/2, (d*(a + b*x))/(-(b*c) + a*d)]))/(21*d*(b*c - a*d)^2*(c + d*x)^(3/2))

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Maple [B]  time = 0.02, size = 750, normalized size = 3.4 \begin{align*} \text{result too large to display} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x*(b*x+a)^(5/2)/(d*x+c)^(5/2),x)

[Out]

1/24*(b*x+a)^(1/2)*(45*ln(1/2*(2*b*d*x+2*((b*x+a)*(d*x+c))^(1/2)*(b*d)^(1/2)+a*d+b*c)/(b*d)^(1/2))*x^2*a^2*b*d
^4-150*ln(1/2*(2*b*d*x+2*((b*x+a)*(d*x+c))^(1/2)*(b*d)^(1/2)+a*d+b*c)/(b*d)^(1/2))*x^2*a*b^2*c*d^3+105*ln(1/2*
(2*b*d*x+2*((b*x+a)*(d*x+c))^(1/2)*(b*d)^(1/2)+a*d+b*c)/(b*d)^(1/2))*x^2*b^3*c^2*d^2+12*x^3*b^2*d^3*((b*x+a)*(
d*x+c))^(1/2)*(b*d)^(1/2)+90*ln(1/2*(2*b*d*x+2*((b*x+a)*(d*x+c))^(1/2)*(b*d)^(1/2)+a*d+b*c)/(b*d)^(1/2))*x*a^2
*b*c*d^3-300*ln(1/2*(2*b*d*x+2*((b*x+a)*(d*x+c))^(1/2)*(b*d)^(1/2)+a*d+b*c)/(b*d)^(1/2))*x*a*b^2*c^2*d^2+210*l
n(1/2*(2*b*d*x+2*((b*x+a)*(d*x+c))^(1/2)*(b*d)^(1/2)+a*d+b*c)/(b*d)^(1/2))*x*b^3*c^3*d+54*x^2*a*b*d^3*((b*x+a)
*(d*x+c))^(1/2)*(b*d)^(1/2)-42*x^2*b^2*c*d^2*((b*x+a)*(d*x+c))^(1/2)*(b*d)^(1/2)+45*ln(1/2*(2*b*d*x+2*((b*x+a)
*(d*x+c))^(1/2)*(b*d)^(1/2)+a*d+b*c)/(b*d)^(1/2))*a^2*b*c^2*d^2-150*ln(1/2*(2*b*d*x+2*((b*x+a)*(d*x+c))^(1/2)*
(b*d)^(1/2)+a*d+b*c)/(b*d)^(1/2))*a*b^2*c^3*d+105*ln(1/2*(2*b*d*x+2*((b*x+a)*(d*x+c))^(1/2)*(b*d)^(1/2)+a*d+b*
c)/(b*d)^(1/2))*b^3*c^4-48*x*a^2*d^3*((b*x+a)*(d*x+c))^(1/2)*(b*d)^(1/2)+316*x*a*b*c*d^2*((b*x+a)*(d*x+c))^(1/
2)*(b*d)^(1/2)-280*x*b^2*c^2*d*((b*x+a)*(d*x+c))^(1/2)*(b*d)^(1/2)-32*a^2*c*d^2*((b*x+a)*(d*x+c))^(1/2)*(b*d)^
(1/2)+230*a*b*c^2*d*((b*x+a)*(d*x+c))^(1/2)*(b*d)^(1/2)-210*b^2*c^3*((b*x+a)*(d*x+c))^(1/2)*(b*d)^(1/2))/((b*x
+a)*(d*x+c))^(1/2)/(b*d)^(1/2)/(d*x+c)^(3/2)/d^4

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Maxima [F(-2)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*(b*x+a)^(5/2)/(d*x+c)^(5/2),x, algorithm="maxima")

[Out]

Exception raised: ValueError

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Fricas [A]  time = 8.64899, size = 1364, normalized size = 6.14 \begin{align*} \left [\frac{15 \,{\left (7 \, b^{2} c^{4} - 10 \, a b c^{3} d + 3 \, a^{2} c^{2} d^{2} +{\left (7 \, b^{2} c^{2} d^{2} - 10 \, a b c d^{3} + 3 \, a^{2} d^{4}\right )} x^{2} + 2 \,{\left (7 \, b^{2} c^{3} d - 10 \, a b c^{2} d^{2} + 3 \, a^{2} c d^{3}\right )} x\right )} \sqrt{\frac{b}{d}} \log \left (8 \, b^{2} d^{2} x^{2} + b^{2} c^{2} + 6 \, a b c d + a^{2} d^{2} + 4 \,{\left (2 \, b d^{2} x + b c d + a d^{2}\right )} \sqrt{b x + a} \sqrt{d x + c} \sqrt{\frac{b}{d}} + 8 \,{\left (b^{2} c d + a b d^{2}\right )} x\right ) + 4 \,{\left (6 \, b^{2} d^{3} x^{3} - 105 \, b^{2} c^{3} + 115 \, a b c^{2} d - 16 \, a^{2} c d^{2} - 3 \,{\left (7 \, b^{2} c d^{2} - 9 \, a b d^{3}\right )} x^{2} - 2 \,{\left (70 \, b^{2} c^{2} d - 79 \, a b c d^{2} + 12 \, a^{2} d^{3}\right )} x\right )} \sqrt{b x + a} \sqrt{d x + c}}{48 \,{\left (d^{6} x^{2} + 2 \, c d^{5} x + c^{2} d^{4}\right )}}, -\frac{15 \,{\left (7 \, b^{2} c^{4} - 10 \, a b c^{3} d + 3 \, a^{2} c^{2} d^{2} +{\left (7 \, b^{2} c^{2} d^{2} - 10 \, a b c d^{3} + 3 \, a^{2} d^{4}\right )} x^{2} + 2 \,{\left (7 \, b^{2} c^{3} d - 10 \, a b c^{2} d^{2} + 3 \, a^{2} c d^{3}\right )} x\right )} \sqrt{-\frac{b}{d}} \arctan \left (\frac{{\left (2 \, b d x + b c + a d\right )} \sqrt{b x + a} \sqrt{d x + c} \sqrt{-\frac{b}{d}}}{2 \,{\left (b^{2} d x^{2} + a b c +{\left (b^{2} c + a b d\right )} x\right )}}\right ) - 2 \,{\left (6 \, b^{2} d^{3} x^{3} - 105 \, b^{2} c^{3} + 115 \, a b c^{2} d - 16 \, a^{2} c d^{2} - 3 \,{\left (7 \, b^{2} c d^{2} - 9 \, a b d^{3}\right )} x^{2} - 2 \,{\left (70 \, b^{2} c^{2} d - 79 \, a b c d^{2} + 12 \, a^{2} d^{3}\right )} x\right )} \sqrt{b x + a} \sqrt{d x + c}}{24 \,{\left (d^{6} x^{2} + 2 \, c d^{5} x + c^{2} d^{4}\right )}}\right ] \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*(b*x+a)^(5/2)/(d*x+c)^(5/2),x, algorithm="fricas")

[Out]

[1/48*(15*(7*b^2*c^4 - 10*a*b*c^3*d + 3*a^2*c^2*d^2 + (7*b^2*c^2*d^2 - 10*a*b*c*d^3 + 3*a^2*d^4)*x^2 + 2*(7*b^
2*c^3*d - 10*a*b*c^2*d^2 + 3*a^2*c*d^3)*x)*sqrt(b/d)*log(8*b^2*d^2*x^2 + b^2*c^2 + 6*a*b*c*d + a^2*d^2 + 4*(2*
b*d^2*x + b*c*d + a*d^2)*sqrt(b*x + a)*sqrt(d*x + c)*sqrt(b/d) + 8*(b^2*c*d + a*b*d^2)*x) + 4*(6*b^2*d^3*x^3 -
105*b^2*c^3 + 115*a*b*c^2*d - 16*a^2*c*d^2 - 3*(7*b^2*c*d^2 - 9*a*b*d^3)*x^2 - 2*(70*b^2*c^2*d - 79*a*b*c*d^2
+ 12*a^2*d^3)*x)*sqrt(b*x + a)*sqrt(d*x + c))/(d^6*x^2 + 2*c*d^5*x + c^2*d^4), -1/24*(15*(7*b^2*c^4 - 10*a*b*
c^3*d + 3*a^2*c^2*d^2 + (7*b^2*c^2*d^2 - 10*a*b*c*d^3 + 3*a^2*d^4)*x^2 + 2*(7*b^2*c^3*d - 10*a*b*c^2*d^2 + 3*a
^2*c*d^3)*x)*sqrt(-b/d)*arctan(1/2*(2*b*d*x + b*c + a*d)*sqrt(b*x + a)*sqrt(d*x + c)*sqrt(-b/d)/(b^2*d*x^2 + a
*b*c + (b^2*c + a*b*d)*x)) - 2*(6*b^2*d^3*x^3 - 105*b^2*c^3 + 115*a*b*c^2*d - 16*a^2*c*d^2 - 3*(7*b^2*c*d^2 -
9*a*b*d^3)*x^2 - 2*(70*b^2*c^2*d - 79*a*b*c*d^2 + 12*a^2*d^3)*x)*sqrt(b*x + a)*sqrt(d*x + c))/(d^6*x^2 + 2*c*d
^5*x + c^2*d^4)]

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Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*(b*x+a)**(5/2)/(d*x+c)**(5/2),x)

[Out]

Timed out

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Giac [B]  time = 1.74793, size = 545, normalized size = 2.45 \begin{align*} \frac{{\left ({\left (3 \,{\left (b x + a\right )}{\left (\frac{2 \,{\left (b^{5} c d^{6}{\left | b \right |} - a b^{4} d^{7}{\left | b \right |}\right )}{\left (b x + a\right )}}{b^{4} c d^{7} - a b^{3} d^{8}} - \frac{7 \, b^{6} c^{2} d^{5}{\left | b \right |} - 10 \, a b^{5} c d^{6}{\left | b \right |} + 3 \, a^{2} b^{4} d^{7}{\left | b \right |}}{b^{4} c d^{7} - a b^{3} d^{8}}\right )} - \frac{20 \,{\left (7 \, b^{7} c^{3} d^{4}{\left | b \right |} - 17 \, a b^{6} c^{2} d^{5}{\left | b \right |} + 13 \, a^{2} b^{5} c d^{6}{\left | b \right |} - 3 \, a^{3} b^{4} d^{7}{\left | b \right |}\right )}}{b^{4} c d^{7} - a b^{3} d^{8}}\right )}{\left (b x + a\right )} - \frac{15 \,{\left (7 \, b^{8} c^{4} d^{3}{\left | b \right |} - 24 \, a b^{7} c^{3} d^{4}{\left | b \right |} + 30 \, a^{2} b^{6} c^{2} d^{5}{\left | b \right |} - 16 \, a^{3} b^{5} c d^{6}{\left | b \right |} + 3 \, a^{4} b^{4} d^{7}{\left | b \right |}\right )}}{b^{4} c d^{7} - a b^{3} d^{8}}\right )} \sqrt{b x + a}}{12 \,{\left (b^{2} c +{\left (b x + a\right )} b d - a b d\right )}^{\frac{3}{2}}} - \frac{5 \,{\left (7 \, b^{2} c^{2}{\left | b \right |} - 10 \, a b c d{\left | b \right |} + 3 \, a^{2} d^{2}{\left | b \right |}\right )} \log \left ({\left | -\sqrt{b d} \sqrt{b x + a} + \sqrt{b^{2} c +{\left (b x + a\right )} b d - a b d} \right |}\right )}{4 \, \sqrt{b d} d^{4}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*(b*x+a)^(5/2)/(d*x+c)^(5/2),x, algorithm="giac")

[Out]

1/12*((3*(b*x + a)*(2*(b^5*c*d^6*abs(b) - a*b^4*d^7*abs(b))*(b*x + a)/(b^4*c*d^7 - a*b^3*d^8) - (7*b^6*c^2*d^5
*abs(b) - 10*a*b^5*c*d^6*abs(b) + 3*a^2*b^4*d^7*abs(b))/(b^4*c*d^7 - a*b^3*d^8)) - 20*(7*b^7*c^3*d^4*abs(b) -
17*a*b^6*c^2*d^5*abs(b) + 13*a^2*b^5*c*d^6*abs(b) - 3*a^3*b^4*d^7*abs(b))/(b^4*c*d^7 - a*b^3*d^8))*(b*x + a) -
15*(7*b^8*c^4*d^3*abs(b) - 24*a*b^7*c^3*d^4*abs(b) + 30*a^2*b^6*c^2*d^5*abs(b) - 16*a^3*b^5*c*d^6*abs(b) + 3*
a^4*b^4*d^7*abs(b))/(b^4*c*d^7 - a*b^3*d^8))*sqrt(b*x + a)/(b^2*c + (b*x + a)*b*d - a*b*d)^(3/2) - 5/4*(7*b^2*
c^2*abs(b) - 10*a*b*c*d*abs(b) + 3*a^2*d^2*abs(b))*log(abs(-sqrt(b*d)*sqrt(b*x + a) + sqrt(b^2*c + (b*x + a)*b
*d - a*b*d)))/(sqrt(b*d)*d^4)